3.11.25 \(\int \frac {(e x)^m}{(a+b x^n) (c+d x^n)} \, dx\) [1025]

Optimal. Leaf size=114 \[ \frac {b (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {b x^n}{a}\right )}{a (b c-a d) e (1+m)}-\frac {d (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {d x^n}{c}\right )}{c (b c-a d) e (1+m)} \]

[Out]

b*(e*x)^(1+m)*hypergeom([1, (1+m)/n],[(1+m+n)/n],-b*x^n/a)/a/(-a*d+b*c)/e/(1+m)-d*(e*x)^(1+m)*hypergeom([1, (1
+m)/n],[(1+m+n)/n],-d*x^n/c)/c/(-a*d+b*c)/e/(1+m)

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Rubi [A]
time = 0.07, antiderivative size = 114, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {522, 371} \begin {gather*} \frac {b (e x)^{m+1} \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {b x^n}{a}\right )}{a e (m+1) (b c-a d)}-\frac {d (e x)^{m+1} \, _2F_1\left (1,\frac {m+1}{n};\frac {m+n+1}{n};-\frac {d x^n}{c}\right )}{c e (m+1) (b c-a d)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(e*x)^m/((a + b*x^n)*(c + d*x^n)),x]

[Out]

(b*(e*x)^(1 + m)*Hypergeometric2F1[1, (1 + m)/n, (1 + m + n)/n, -((b*x^n)/a)])/(a*(b*c - a*d)*e*(1 + m)) - (d*
(e*x)^(1 + m)*Hypergeometric2F1[1, (1 + m)/n, (1 + m + n)/n, -((d*x^n)/c)])/(c*(b*c - a*d)*e*(1 + m))

Rule 371

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p*((c*x)^(m + 1)/(c*(m + 1)))*Hyperg
eometric2F1[-p, (m + 1)/n, (m + 1)/n + 1, (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rule 522

Int[((e_.)*(x_))^(m_.)/(((a_) + (b_.)*(x_)^(n_))*((c_) + (d_.)*(x_)^(n_))), x_Symbol] :> Dist[b/(b*c - a*d), I
nt[(e*x)^m/(a + b*x^n), x], x] - Dist[d/(b*c - a*d), Int[(e*x)^m/(c + d*x^n), x], x] /; FreeQ[{a, b, c, d, e,
n, m}, x] && NeQ[b*c - a*d, 0]

Rubi steps

\begin {align*} \int \frac {(e x)^m}{\left (a+b x^n\right ) \left (c+d x^n\right )} \, dx &=\frac {b \int \frac {(e x)^m}{a+b x^n} \, dx}{b c-a d}-\frac {d \int \frac {(e x)^m}{c+d x^n} \, dx}{b c-a d}\\ &=\frac {b (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {b x^n}{a}\right )}{a (b c-a d) e (1+m)}-\frac {d (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {d x^n}{c}\right )}{c (b c-a d) e (1+m)}\\ \end {align*}

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Mathematica [A]
time = 0.09, size = 88, normalized size = 0.77 \begin {gather*} \frac {x (e x)^m \left (-b c \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {b x^n}{a}\right )+a d \, _2F_1\left (1,\frac {1+m}{n};\frac {1+m+n}{n};-\frac {d x^n}{c}\right )\right )}{a c (-b c+a d) (1+m)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(e*x)^m/((a + b*x^n)*(c + d*x^n)),x]

[Out]

(x*(e*x)^m*(-(b*c*Hypergeometric2F1[1, (1 + m)/n, (1 + m + n)/n, -((b*x^n)/a)]) + a*d*Hypergeometric2F1[1, (1
+ m)/n, (1 + m + n)/n, -((d*x^n)/c)]))/(a*c*(-(b*c) + a*d)*(1 + m))

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Maple [F]
time = 0.11, size = 0, normalized size = 0.00 \[\int \frac {\left (e x \right )^{m}}{\left (a +b \,x^{n}\right ) \left (c +d \,x^{n}\right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x)^m/(a+b*x^n)/(c+d*x^n),x)

[Out]

int((e*x)^m/(a+b*x^n)/(c+d*x^n),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x)^m/(a+b*x^n)/(c+d*x^n),x, algorithm="maxima")

[Out]

integrate((x*e)^m/((b*x^n + a)*(d*x^n + c)), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x)^m/(a+b*x^n)/(c+d*x^n),x, algorithm="fricas")

[Out]

integral((x*e)^m/(b*d*x^(2*n) + a*c + (b*c + a*d)*x^n), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (e x\right )^{m}}{\left (a + b x^{n}\right ) \left (c + d x^{n}\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x)**m/(a+b*x**n)/(c+d*x**n),x)

[Out]

Integral((e*x)**m/((a + b*x**n)*(c + d*x**n)), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x)^m/(a+b*x^n)/(c+d*x^n),x, algorithm="giac")

[Out]

integrate((x*e)^m/((b*x^n + a)*(d*x^n + c)), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (e\,x\right )}^m}{\left (a+b\,x^n\right )\,\left (c+d\,x^n\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x)^m/((a + b*x^n)*(c + d*x^n)),x)

[Out]

int((e*x)^m/((a + b*x^n)*(c + d*x^n)), x)

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